Figure shown the kinetic energy `K` of a pendulum versus. its angle `theta` from the verticle. The pendulum bob has mass `0.2kg` The length of the pendulum is equal to `(g = 10m//s^(2))`
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Figure shown the kinetic energy K of a pendulum versus. its angle theta from the vertical. The pendulum bob has mass 0.2kg The length of the pendulum is equal to (g = 10m//s^(2)) ,

Figure shows the kinetic energy K of a simple pendulum versus its angle theta from the verticle. The pendulum bob has mass 0.2 kg . If the length of the pendulum is equal to (n)/(g) meter. Then find n (g = 10 m//s^(2))

The given figure shows the variation of the kinetic energy of a simple pendulum with its angular displacement (theta) from the vertical. Mass of the pendulum bob is m = 0.2 kg. Find the time period of the pendulum. Take g = 10 ms^(-2) .

A 1N pendulum bob is held at an angle theta from the vertical by a 2N horizontal force F as shown in figure. The The tension in the string supporting the pendulum bob (in newton) is .

The time period of a pendulum of length 'l' and mass of the bob 'm' is T. Time period of a pendulum with mass of the bob 2m and length l is ______.

A simple pendulum is released from A as shown. If m and 1 represent the mass of the bob and length of the pendulum, the gain kinetic energy at B is

A simple pendulum is released from A as shown. If m and 1 represent the mass of the bob and length of the pendulum, the gain kinetic energy at B is