In a circle of radius `r ,` chords of length `aa n dbc m` subtend angles `thetaa n d3theta` , respectively, at the center. Show that `r=asqrt(a/(3a-b))c m`

In a circle of radius r , chords of length a and b cm subtend angles thetaa n d3theta , respectively, at the center. Show that r=asqrt(a/(3a-b))c m

In a circle of radius r, chords of length a and b cm subtend angles theta and 3 theta , respectively,at the center.Show that r=a sqrt((a)/(3a-b))cm

Two chords of a circle are of lengths a cm and b cm and they subtend angles theta and 3theta respectively at the center of the circl. If the radius of the circle by r cm, show that, r=a sqrt(a/(3a-b)) cm.

Consider a circle of radius R. What is the lengths of a chord which subtends an angle theta at the centre ?

Two parallel chords are drawn on the same side of the centre of a circle of radius R .It is fouind that they subtend angles of theta and 2 theta at the centre of the circle.The prependicular distance between the chords is

Let p and q be the length of two chords of a circle which subtend angles 36^@ and 60^@ respectively at the centre of the circle . Then , the angle (in radian) subtended by the chord of length p + q at the centre of the circle is (use pi=3.1 )

Two parallel chords are drawn on the same side of the centre of a circle of radius R. It is found that they subtend and angle of theta and 2theta at the centre of the circle. The perpendicular distance between the chords is

Two parallel chords are drawn on the same side of the centre of a circle of radius R. It is found that they subtend and angle of theta and 2theta at the centre of the circle. The perpendicular distance between the chords is

Two parallel chords are drawn on the same side of the centre of a circle of radius R. It is found that they subtend and angle of theta and 2theta at the centre of the circle. The perpendicular distance between the chords is