`(f(x y))^2=x(f(y))^2:f(2)=6` A function f: R+ ? R+ defined as Then `f(100) =?`

Let f be a function defined from R^(+)rarrR^(+). If (f(xy))^(2)=x(f(y))^(2) for all positive numbers x and y, If f(2)=6, find f(50) =?

Let f be a function defined from R^(+)rarrR^(+). If (f(xy))^(2)=x(f(y))^(2) for all positive numbers x and y, If f(2)=6, find f(50) =?

If f : R to R is continuous such that f(x + y) = f(x) + f(y) x in R , y in R and f(1) = 2 then f(100) =

If the function f: R to R is defined by f(x)=x^(2)-6x-14 , then f^(-1)(2) is equal to -

3,A function f: R.R ,defined as Then {f(xy)}^(2)=x*(f(y))^(2),f(2)=6 then f(100)

A function R^(+)rarr R^(+) defined as Then (f(xy))^(2)=x(f(y))^(2) and f(2)=6 then f(100) is (A)300(B)30sqrt(2)(C)50sqrt(2)(D)100

Let f be a function defined from R rarr R If [f(xy)]^(2)=x(f(y))^(2) for all positive numbers x and y and f(2)=6 then find f(50)

Let f(x+y)=f(x)*f(y)AA x,y in R and f(0)!=0* Then the function phi defined by .Then the function phi(x)=(f(x))/(1+(f(x))^(2)) is

A function f : R rarr defined by f(x) = x^(2) . Determine {y : f(y) = - 1}