The plane `x - 2y + z = 6` and line `x/1=y/2=z/3` are related as the line :

The plane x- 2y +z-6 = 0 and the line x/1=y/2=z/3 are related as:

The plane x-2y+z-6=0 and the line x/1=y/2=z/3 are related as the line (A) meets the plane obliquely (B) lies in the plane (C) meets at righat angle to the plane (D) parallel to the plane

The plane x-2y+z-6=0 and the line x/1=y/2=z/3 are related as the line (A) meets the plane obliquely (B) lies in the plane (C) meets at righat angle to the plane (D) parallel to the plane

The line (x)/(1) = y/2=z/3 and the plane x-2y+ z=0:

The line (x)/(1) = y/2=z/3 and the plane x-2y+ z=0:

If line L:x/1 = y/2 =z/3 and plane E:x-2y +z=6 , then the line L

The equation of the plane passing through the line of intersection of the planes x+y+z+3 =0 and 2x-y + 3z +2 =0 and parallel to the line (x)/(1) = (y)/(2) = (z)/(3) is