Find the equation of the circle with radius 5 whose centre lies on x–axis and passes through the point (2, 3).

Explanation

To find the equation of the circle with radius 5, whose center lies on the x-axis and passes through the point (2, 3), we can follow these steps:

### Step 1: Identify the center and radius of the circle
The standard form of the equation of a circle is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]
where \((h, k)\) is the center of the circle and \(r\) is the radius.
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