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in the adjoining figure, AB=AC and AD=AE...

in the adjoining figure, AB=AC and AD=AE. Prove that 1. `/_ADB=/_AEC` 2. `DeltaABD~=DeltaACE` 3. BE=DC

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`/_ABE=/_ACE `(Isosceles)
`/_ADE=/_AED`(Isosceles)
1)`180-/_ADE=180-/_AED`
`/_ADB=/_AEC`
2)`In/_ABD and /_ACE`
`/_ABD=/_ACE`
`/_ADB=/_AEC`
`/_BAD=/_CAE`
...
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