ax+by=a-b ; bx-ay=a+b

A, B C and D are the points of intersection with the coordinate axes of the lines ax+by=ab and bx+ay=ab , then

A, B C and D are the points of intersection with the coordinate axes of the lines ax+by=ab and bx+ay=ab, then

A,B,C,D are the points of intersection with the coordinate axes of the line ax+by=ab and bx+ay=ab. Then

A, B C and D are the points of intersection with the coordinate axes of the lines ax+by=ab and bx+ay=ab, then

Solve: ax+by=a-b,quad bx-ay=a+b

Solve the following system of equations by method of cross-multiplication: ax+by=a-b,quad bx-ay=a+b

ax+by=a+b bx+ay=b^2

Solve the following pair of linear equations by substitution method : ax+by = a^2 , bx+ay= b^2 .

If ax+by=6, bx-ay=2and x^(2)+y^(2)=4 then what is (a^(2)+b^(2)) ?