In the previous problem , if a bomb explodes into three parts of mass ratio `1 : 1 : 2` , one smaller part retraces its path, the second smaller part coming to rest, the distance from the point of projection , where the heavier part strikes the ground is

A bomb of mass 4m explodes into two parts of mass ratio 1 : 3. If k be the kinetic energy of larger part then K.E. of small part

A bomb of mass 4m explodes into two parts of mass ratio 1 : 3. If k be the kinetic energy of larger part then K.E. of small part

A bomb of mass 4 m , while moving on a parabolic path, explodes at highest point of its path. If breaks into two parts of mass ratio 1 : 3 , smaller part coming to rest. The range of this projectile was 60 m in the absence of explosion. The distance of the second part from the point of projection when it strikes the ground is

A bomb is thrown at a speed 20 m//s at an angle 45^(@) . At the highest point , it explodes into two parts of equal mass , the one part coming to rest. Find the distance from the origin to the point where the other part strikes the ground.

A body is projected with a speed 160 m/s at an angle 53^(@) with the horizontal, At the highest point, body explodes into two pieces with mass ratio 1:3. Smaller piece comes to rest immediately after explosion. Find the distance of point from point of projection where heavier piece strikes the horizontal surface.

A bomb of mass 4 m explodes into two parts of mass ratio 1 : 3 . If the K.E . Of smaller fragment is K , find the K.E. of the larger fragment.