The equation of a transverse wave travelling on a rope given by `y=10sinpi(0.01x-2.00t)` whrer y and x are in cm and t in second .This maximum traverse speed of a particle in the rope is about

The equation of a transverse travelling on a rope is given by y=10sinpi (0.01x-2.00t) where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about

The equation of a transverse travelling on a rope is given by y=10sinpi (0.01x-2.00t) where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about

The equation of a transverse wave travelling on a rope is given by y = 10sin pi (0.01x-2.000t) where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about

The equation of a transverse wave travelling on a rope is given by y =10 sin pi (0.01xx -2.00t) where y and x are in cm and t is in seconds. The maximum transverse speed of a particle in the rope is about

The equation of a transverse wave travelling in a rope is given by y = 5 sin (4t - 0.02 x) , where y and x are in cm and time t is in second. Then the maximum transverse speed of wave in the rope is

The equation of a transverse wave is given by y=10 sin pi (0.01 x -2t ) where x and y are in cm and t is in second. Its frequency is

The equation of a transverse wave is given by y=10 sin pi (0.01 x -2t ) where x and y are in cm and t is in second. Its frequency is