A particle is performing simple harmonic motion with amplitude A and angular velocity `omega` . The ratio of maximum velocity to maximum acceleration is

A particle executing simple harmonic motion with an amplitude A and angularr frequency omega . The ratio of maximum acceleration to the maximum velocity of the particle is

A particle executing simple harmonic motion with an amplitude A and angularr frequency omega . The ratio of maximum acceleration to the maximum velocity of the particle is

A 0.5 kg body performs simple harmonic motion with a frequency of 2 Hz and an amplitude of 8 mm . Find the maximum velocity of the body, its maximum acceleration and the maximum restoring force to which the body is subjected.

A 0.5 kg body performs simple harmonic motion with a frequency of 2 Hz and an amplitude of 8 mm . Find the maximum velocity of the body, its maximum acceleration and the maximum restoring force to which the body is subjected.

The total work done by a restoring force in simple harmonic motion of amplitude A and angular velocity. omega , in one oscillation is

The total work done by the restoring force in simple harmonic motion of amplitude A and angular velocity omega in one oscillation is

A particle is executing simple harmonic motion with an amplitude of 0.02 metre and frequency 50 Hz . The maximum acceleration of the particle is

In simple harmonic motion, at which position the velocity and acceleration are maximum.

For a particle in SHM the amplitude and maximum velocity are A and V respectively. Then its maximum acceleration is