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Kinetic energy of the particle is E and ...

Kinetic energy of the particle is E and it's De-Broglie wavelength is `lambda`. On increasing it's KE by `delta E`, it's new De-Broglie wavelength becomes `lambda/2`. Then `delta E` is

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de-Broglie wavelength lambda is

The de-Broglie wavelength lambda

If the kinetic energy of a particle is doubled, De-Broglie wavelength becomes :

For particles having same K.E., the de-Broglie wavelength is

For particles having same K.E., the de-Broglie wavelength is

De Broglie wavelength lambda is proportional to

De Broglie wavelength lambda is proportional to

If the kinetic energy of a particle is doubled, de Broglie wavelength becomes: