For an electrolyte solution of `0.05 mol L^(-1)` , the conductivity has been found to be `0.0110S cm^(-1)`. The molar conductivity is

For an electrolyte solution of 0.05 mol L^(-1) , the conductivity has been found to be 0.0110 S cm^(-1) . The molar conductivity is

For an electrolytic solution of 0.05 mole "litre"^(-1) , the conductivity has been found to be 0.0110 S cm^(-1) . The molar conductivity (in Scm^(2) "mole"^(-1) ) is

For an electrolytic solution of 0.05 mol L^(-1) , the specific conductance has been found to be 0.0110"S cm"^(-1) . The molar conductance is :

The conductivity of a solution containing 1.0 g of anhydrous BaCl_2 in 200 cm^3 of the solution has been found to be 0.0058 S cm^-1 . Calculate the molar conductivity and equivalnet conductivity of the solution.

The conductivity of 0.35M solution of KCl at 300K is 0.0275 S cm^(-1) . Calculate molar conductivity

The conductivity of 0.35M solution of KCl at 300K is 0.0275 S cm^(-1) . Calculate molar conductivity

The resistance of a 0.5 M solution of an electrolyte in a conductivity 'cell was found to be 25 ohm. Calculate the molar conductivity of the solution, if the electrodes in the cell are 1.6 cm apart and have an area of 3*2cm^(2) .