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[" i0."(1+tan A+sec A)(1+cot A-csc A)=],...

[" i0."(1+tan A+sec A)(1+cot A-csc A)=],[[" (a) "0," (b) "1" (c) "2quad (d)-1]]

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(1+tan A+sec A)(1+cot A-cosec A)=

(tan A+cot A)=(sec A*csc A)

Prove that (1+tan A+sec A)(1+cot A-" cosec A")=2

" (i) "(1+sec A+tan A)(1-cosec A+cot A)=2

(1 + cot A — cosec A) (1 + tan A + sec A) = 2 .

(1+tan theta+sec theta)(1+cot theta-cosec theta) = ? (a) -1 (b) 0 (c) 2

(1+tan A)/(sin A)+(1+cot A)/(cos A)=2(sec A+cosec A)

sin A(1+tan A)+cos A(1+cot A)=sec A+cosec A

(1+cot A-csc A)(1+tan A+sec A)" is equal to "