In `Delta ABC, AB= AC`. Side BC is produced to D. Prove that `(AD^(2)-AC^(2))=BD*CD`.

In an isoscles Delta ABC, AB= AC and D is a point on BC. Prove that AB^(2)-AD^(2)=BD*CD .

In an isosceles triangle ABC, AB = AC and D is a point on BC produced. Prove that : AD^(2)=AC^(2)+BD.CD

In triangle ABC, AB=AC and BD is perpendicular to AC. Prove that : BD^(2)-CD^(2)=2CDxxAD

In /_ABC,AB=AC and D is any point on BC , prove that AB^(2)-AD^(2)=BD.CD

In Delta ABC , BD : CD = 3 : 1 and AD _|_ BC . Prove that 2(AB^(2) - AC^(2)) = BC^(2) .

Delta ABC, AB = AC and BA is produced to D such that AC = AD. Then the angleBCD is

abc is an isosceles triangle with AB=AC . Side BA is produced to D such that AB=AD. Prove that /_BCD is a right angle

ABC is a triangle in which AB = AC and D is any point on BC. Prove that: AB^(2)- AD^(2) = BD. CD