Consider an elliptically shaped rail PQ in the vertical plane with OP = 3 m and OQ=4 m. A block of mass 1 kg is pulled along the rail from P to Q with a force of 18 N, which is always parallel to line PQ (see figure). Assuming no frictional losses, the kinetic energy of the block when it reaches Q is (n * 10)). The value of n is (take acceleration due to gravity = 10 ms?). 1000 L . 0 - 3m

Consider an elliptically shaped rail PQ in the vertical plane with OP = 3 m and OQ = 4 m. A block of mass 1 kg is pulled along the rail from P to Q with a force of 18 N, which is always parallel to line PQ (see the figure given). Assuming no frictional losses, the kinetic energy of the block when it reaches Q is: (n xx 10) joules. The value of n is (take acceleration due to gravity = 10 ms^(-2) ) https://haygot.s3.amazonaws.com/questions/113759.jpg

Constant as eliptical rail PQ in the varticle plain with OP = = 3m and OQ= 4 m . A block of mass 1 kg is pailed along the rail from P to Q with a force of 18 N , which is always parallel to less PQ Assuming are frictionless losess , the kinetic energy the block when 0 reches Q is ( nxx 10) pales . THe velie of a (Take acceleration due to gravity ) = 10ms^(-2))

A block of mass 5 kg is initially at rest on a rough horizontal surface. A force of 45 N acts over a distance of 2 m . The force of friction acting on the block is 25 N . The final kinetic energy of the block is

If the mass of block is 1 kg and a force of 10 / sqrt3 N is applied horizontally on the block as shown in the figure . The frictional force acting on the block is :

A block of mass 4 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 12 N is applied on the block parallel to the floor, the force of friction between the block and floor (g = 10 ms^(-2))

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take g=10 m s^(-2) )

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take g=10 m s^(-2) )

A block of mass "2kg" is placed on the floor.If "a],[" force of "2.8N" is applied on the block parallel at angle of "30" degree from horizontal,then acceleration of block is (take "g=10m/s^(2)" )

A block of mass 10 kg is placed on a horizontal surface as shown in the figure and a force F = 100 N is applied on the block as shown, in the figure. The block is at rest with respect to ground. If the contact force between block and ground is 25n (in Newton) then value of n is : (Take g = 10 m//s^(2))

A block of mass 10 kg is placed on a horizontal surface as shown in the figure and a force F = 100 N is applied on the block as shown, in the figure. The block is at rest with respect to ground. If the contact force between block and ground is 25n (in Newton) then value of n is : (Take g = 10 m//s^(2))