A particle of mass m is projected from the surface of earth with a speed `V_(0)(V_(0) lt` escape velocity). Find the speed of particle at height `h = R` (radius of earth). (Take, `R = 6400 km` and `g = 9.8 m//s^(2))`

A particle is projected from the surface of earth with intial speed of 4 km/s. Find the maximum height attained by the particle. Radius of earth = 6400 km and g = 9.8 m//s^(2)

A particle is projected from the surface of earth with intial speed of 4 km/s. Find the maximum height attained by the particle. Radius of earth = 6400 km and g = 9.8 m//s^(2)

Aparticle is projected from the surface of the earth with an intial speed of 4.0 km//s .Find the maximum height attained by the particle. Radius of earth = 6400km g = 9.8 m//s^(2) .

Aparticle is projected from the surface of the earth with an intial speed of 4.0 km//s .Find the maximum height attained by the particle. Radius of earth = 6400km g = 9.8 m//s^(2) .

When a particle is projected from the surface of earth its mechanical energy and angular momentum about center of earth at all time are constant. Q. A particle of mass m is projected from the surface of earth with velocity v_(0) at angle 0 with horizontal suppose h be the maximum height of particle from surface of earth and v its speed at that point then v is v_(0)cos0

When a particle is projected from the surface of earth its mechanical energy and angular momentum about center of earth at all time are constant. Q. A particle of mass m is projected from the surface of earth with velocity v_(0) at angle 0 with horizontal suppose h be the maximum height of particle from surface of earth and v its speed at that point then v is v_(0)cos0

When a particle is projected from the surface of earth its mechanical energy and angular momentum about center of earth at all time are constant. Q. A particle of mass m is projected from the surface of earth with velocity v_(0) at angle theta with horizontal suppose h be the maximum height of particle from surface of earth and v its speed at that point then v is v_(0)costheta

A particle of mass m is projected upwards from the surface of the earth with a velocity equal to half the escape velocity. (R is radius of earth and M is mass of earth)Calculate the potential energy of the particle at its maximum. Write the kinetic energy of the particle when it was at half the maximum height.

A particle is located 1,800 km above the surface of earth. Calculate the escape velocity of the particle. Take Radius of earth = 6,400 km g = 9.8 m//s^(2)