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An ordinary cube has 4 blank faces, one ...

An ordinary cube has 4 blank faces, one face mark 2 and another marked 3, then the probability of obtaining 12 in 5 throws is

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`P=(1/6)^4*(4/6)5C_1+(1/6)^5*5C_2`
`P=20/6^5+10/6^5=30/6^5=5/12966`
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