A cooking vessel on a slow burner contains 5 kg of water and an unknown mass of ice in equilibrium at `0^@C` at time `t=0`. The temperature of the mixture is measured at various times and the result is plotted as shown in Fig. During the first 50 min the mixture remains at `0^@C`. From 50 min to 60 min, the temperature increases to `2^@C` Neglecting the heat capacity of the vessel, the initial mass of the ice is

If 2g ice at 0^(0)C is dropped into 10g water at 80^(0)C then temperature of mixture is

A container contains 5 kg of water at 0^(@)C mixed to an unknown mass of ice in thermal equilibrium. The water equivalent of the container is 100 g. At time t = 0, a heater is switched on which supplies heat at a constant rate to the container. The temperature of the mixture is measured at various times and the result has been plotted in the given figure. Neglect any heat loss from the mixture – container system to the surrounding and calculate the initial mass of the ice. Given: S_(p) . latent heat of fusion of ice is L_(f) = 80 cal g^(-1) S_(p) . heat capacity of water = 1 cal g^(-1) .^(@)C^(-1)

15 g ice at 0^@C is mixed with 10 g water at 40^@C . Find the temperature of mixture. Also, find mass of water and ice in the mixture.

15 g ice at 0^@C is mixed with 10 g water at 40^@C . Find the temperature of mixture. Also, find mass of water and ice in the mixture.

100g ice at 0^(@)C is mixed with 100g water at 100^(@)C . The resultant temperature of the mixture is

100g ice at 0^(@)C is mixed with 100g water at 100^(@)C . The resultant temperature of the mixture is