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[" Let "A=[[0,-tan(alpha)/(2)],[tan(alph...

[" Let "A=[[0,-tan(alpha)/(2)],[tan(alpha)/(2),0]]" and "I" is the identity matrix of order "2" ."],[[tan(alpha)/(2),0,-sin alpha],[" Show that ",(I+A)=(I-A)*[[cos alpha,-sin alpha],[sin alpha,cos alpha]]]]

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If A=,[[0,-tan((alpha)/(2))]tan((alpha)/(2)),0]], then I+A=(I-A)[[cos alpha,-sin alphasin alpha,cos alpha]]

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A=[[0,-tan((alpha)/(2))tan((alpha)/(2)),0]]then(I-A)[[cos alpha,-sin alphasin alpha,cos alpha