`dy/dx(1+x+y)=x+y+1`

x(dy/dx + y ) = 1 -y

The solution of (dy)/(dx) = (x + y +1)/(x + y -1) is

Solve the following differential equations. dy/dx=(x+y+1)/(x+y-1)

If the homogeneous form of the differential equation (dy)/(dx)=(x + y + 1)/( x - y +1) is (dY)/(dX) = (X + Y)/(X - Y) then what is the relation between Y and y?

Solve the following differential equations: (dy)/(dx)=1+x+y+x y (ii) y-x(dy)/(dx)=a(y^2+(dy)/(dx))

Solve the following differential equations: (dy)/(dx)=1+x+y+x y (ii) y-x(dy)/(dx)=a(y^2+(dy)/(dx))

Solve the following differential equations: (dy)/(dx)=1+x+y+x y (ii) y-x(dy)/(dx)=a(y^2+(dy)/(dx))

Solve (dy)/(dx)sqrt(1+x+y)=x+y-1

If (sinx)^y=x+y , prove that (dy)/(dx)=(1-(x+y)ycotx)/((x+y)logsinx-1)

If (sin"x")^y=x+y ,p rov et h a t(dy)/(dx)=(1-(x+y)ycotx)/((x+y)logsinx-1)