For a molecule of an ideal gas `n=3xx10^(8)cm^(-3)` and mean free path is `10^(-2)` cm. Calculate the diameter of the lomecule.

For a molecule of an ideal gas n=3xx10^(8)cm^(-3) and mean free path is 10^(-2) cm. Calculate the diameter of the molecule.

For a molecule of an ideal gas n=3xx10^(8)cm^(-3) and mean free path is 10^(-2) cm. Calculate the diameter of the molecule.

The mean free path of molecule of a gas is 10^(-8) cm. If number density of gas is 10^(9)//cm^(3) . Calculate the diameter of the molecule.

The mean free path of molecules of a gas is 10^(-8) cm. if number density of gas is 10^(9)//cm^(3) calculate the diameter of the molecule

The mean free path of molecules of a gas is 10^(-8) cm. if number density of gas is 10^(9)//cm^(3) calculate the diameter of the molecule

if the mean free path of a molecule of an ideal gas having diameter 10^(-8)cm is 10^(-4) cm, calculate the number density of the gas molecule.

For a molecule of an ideal gas, the number density is 2sqrt(2)xx10^(8) cm^(-3) and the mean free path is (10^(-2))/(pi) cm . The diameter of the gas molecule is

If the mean free path of a molecule of an ideal gas having diameter 10^(-8) cm is 10^(-4) m, calculate the number density of the gas.