An electric heater of power 100 W raises the temperature of 5 kg of a liquid from `25^(@)C` to `31^(@)C` in 2 minutes. Calculate the specific heat of the liquid.

An electric heater of power 1000 W raises the temperature of 5 kg of a liquid from 25^@ C to 31^@ C in 2 minutes. Calculate : (i) the heat capacity, and (ii) the specific heat capacity of liquid.

An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0^@ C to 15.0^@ C in 100 s. Calculate : (i) the heat capacity of 4.0 kg of liquid, and (ii) the specific heat capacity of liquid.

How much heat energy is necessary to raise the temperature of 5 kg of water from 20^@C to 100^@C

1300 J of heat energy is supplied to raise the temperature of 0.5 kg of lead from 20^@ C to 40^@ C. Calculate the specific heat capacity of lead.

An energy of 84000 J is required to raise the temperature of 2 kg of water from 60^@ C " to " 70^@ C . Calculate the specific heat capacity of water.

How much heat energy is necessary to raise the temperature of 5 kg of water from 20 ^@ C " to " 100^@C ?

A liquid having mass m = 250 g is kept warm in a vessel by use of an electric heater. The liquid is maintained at 50^(@)C when the power supplied by heater is 30 watt and surrounding temperature is 20^(@)C . As the heater is switched off, the liquid starts cooling and it was observed that it took 10 second for temperature to fall down from 40^(@)C to 39.9^(@)C . Calculate the specific heat capacity of the liquid. Assume Newton’s law of cooling to be applicable.

A liquid of mass 250 g is kept warm in a vessel using an electric heater. The liquid is maintained at 57^(@) when the power supplied by the heater is 30 W and surrounding temperature is 27^(@) C . As the heater is switched off, it took 10 s time for the temperature of the liquid to fall from 47^(@) C to 46.9^(@) C . The specific heat capacity of the liquid is