When a ray of light is refracted by a prism such that the angle of deviation is minimum, then

(a) If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then find the angle of incidence. (b) A ray of light passes through an equilateral prism such that the angle of emergence is equal to the angle of incidence and each is equal to 3//4^(th) of the angle of prism. Find the angle of deviation. (c) The refracting of a prism is A and the refractive index of the material of the prism is cotA//2 . Find the angle of deviation. (d) The angle of a prism is 60^@ . What is the angle of incidence for minimum deviation? The refractive index of the material of the prism is sqrt2 .

The refracting angle of a prism is A and the refractive index of its material is cot A//2 .For a ray of light incident on the prism,find the angle of minimum deviation in terms of A.

The angle of incidence for a ray of light at a refracting surface of a prism is 45^@ . The angle of prism is 60^@ . If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are

The angle of incidence for a ray of light of a refracting surface of at prism is 45^@ . The angle of prism is 60^@ . If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are

The angle of incidence for a ray of light at a refracting surface of a prism is 45^(@) . The angle of prism is 60^(@) . If the ray suffers minimum deviation through the prism. The angle of minimum deviation and refractive index of the material of the prism respectively, are