The smallest number of terms which may be taken in order that the sum of the A.P. `325 +350 +375 +....` may exceed 10,000 is.

The number of terms of the A.P. 1,4,7,… that must be taken to obtain a sum of 715 is

The numbers of terms of the A.P 3, 7, 11, 15, …… to be taken so that the sum is 406 is

The number of terms of the A.P. 3,7,11,15, "…." to be taken so that their sum is 406 , is

Find the number of terms of the A.P. 98,91,84,…must be taken to give a sum of zero :

Calculate the least number of terms of the geometric progression 5 + 10 + 20 + ... whose sum would exceed 10,00,000.

If 10th term of an A.P is 13, then the sum of 19 terms =

What is the sum of first 10 terms of the A.P. 15, 10 ,5 ….?

The number of terms of an A.P. is even the sum of the odd terms is 24 sum of the even terms is 30 and the last term exceeds the first by 10 (1)/(2) then the number of terms in the series is

The number of terms in an A.P.is even; the sum of the odd terms is 24, of the even terms 30, and the last term exceeds the first by 10 find the number of terms

The number of terms of an A.P. is even; the sum of the odd terms is 310; the sum of the even terms is 340; the last term exceeds the first by 57. Then,