`420 J` of energy supplied to `10g` of water will rises its temperature by

If 'm' g of fuel is completely burned and that heat energy is supplied to 'M' g of water to raise its temperature by Deltat^(@)C then arrange the following steps in a sequences to calculate the calorific value of the fuel (a) Determine the heat energy absorbed by water (b) Determine the calorific value by dividing heat energy produced with mass of the fuel (c ) Note down the amss of water specific heat capacity and change in temperature of water (d) Heat energy absorbed by water is equal to heat given by the guel after complete combustion

When 60 calories of heat are supplied to 15 g of water, the rise in temperature is

50 g of copper is heated to increase its temperature by 10^@C . If the same quantity of heat is given to 10g of water, the rise in its temperature is (specific heat of copper =420J//kg^(@)//C )

50 g of copper is heated to increase its temperature by 10^@C . If the same quantity of heat is given to 10g of water, the rise in its temperature is (specific heat of copper =420J//kg^(@)//C )

10 g of water is supplied with 420 J of energy. The rise in temperature of water is

50 g of copper is heated to increase its temperature by 10^(@)C . If the same quantity is given to 10 g of water, what will be the rise in its temperature (in .^(@)C )?

50 gm of copper is heated to increase its temperature by 10^(@)C. If the same quantity of heat is given to 10 gm of water, the rise in its temperature is (Specific heat of copper =420 Joule-kg^(-1)@C^(-1)

Some heat energy is given to 120 g of water and its temperature rises by 10 K. When the same amount of heat energy is given to 60 g of oil, its temperature rises by 40 K. The specific heat capacity of water is 4200 J kg- K^(-1) . Calculate : (i) the amount of heat energy in joule given to water, and (ii) the specific heat capacity of oil.