What is the momentum of an object of mass m moving with a velocity v?
(a) `(mv)^(2)`
(b) `mv^(2)`
(c) `1/2 mv^(2)`
(d) mv

Answer true or false. K.E. of an object of mass m movig with velocity v is equal to 1/2 mv

The kinetic energy passessed by a body of mass m moving with a velocity v is equal to (1)/(2)mv^(2) , provided

The momentum of a particle of mass of m moving with a velocity v is p= mv. What is the rate of change of momentum ? Assume that m is constant .

If a body of mass m is moving with velocity v then prove that kinetic energy of the body = frac(1)(2) mv^2

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma

The SI unit of energy is J=kg m^(2)s^(-2) , that of speed v is ms^(-1) and of acceleration a is ms^(-2) . What of the formulae for kinetic energy (k) given below can you rule out on the basis of dimensional arguments (m stands for the mass of the body) : (a) K = m^(2)v^(2) (b) K = (1/2)mv^(2) ("c") K= ma (d) K = (3/16)mv^(2) (e) K=(1/2)mv^(2)+ma