Let `f(x)=x^2-bx+ c`, b is a odd positive integer, `f(x) = 0` have two prime numbers as roots and `b+c=35` Then the global minimum value of f(x) is

Let f(x)=x^2-bx+c,b is an odd positive integer. Given that f(x)=0 has two prime numbers as roots and b+c=35. If the least value of f(x) AA x in R" is "lambda," then "[|lambda/3|] is equal to (where [.] denotes greatest integer function)

Let f(x)=x^2-bx+c,b is an odd positive integer. Given that f(x)=0 has two prime numbers as roots and b+c=35. If the least value of f(x) AA x in R" is "lambda," then "[|lambda/3|] is equal to (where [.] denotes greatest integer function)

Let f (x) =x ^(2)-bx+c,b is an odd positive integer. Given that f (x)=0 has two prime numbers an roots and b+c =35. If the least value of f (x) AA x in R is lamda, then |(lamda)/(3)| is equal to (where [.] denotes greatest integer functio)

Let f(x)=x^(2)-ax+b , 'a' is odd positive integar and the roots of the equation f(x)=0 are two distinct prime numbers. If a+b=35 , then the value of f(10)=

Let f(x)=x^(2)-ax+b , 'a' is odd positive integar and the roots of the equation f(x)=0 are two distinct prime numbers. If a+b=35 , then the value of f(10)=

Let f(x)=x^(2)-ax+b , 'a' is odd positive integar and the roots of the equation f(x)=0 are two distinct prime numbers. If a+b=35 , then the value of f(10)=

Let f(x)=x^(2)-ax+b , 'a' is odd positive integar and the roots of the equation f(x)=0 are two distinct prime numbers. If a+b=35 , then the value of f(10)=

Let f(x)=x^2-ax + b, where a is an odd positive integer and the roots of the equation f(x) = 0 are two distinct prime numbers. If a + b = 35 then, the value of ([f(0)+f(2)+f(3)+...+f(10)] xx f(10))/440=0........

Suppose x^(2)+bx+c {b is an odd integer and c in Z } has two prime natural numbers as its roots . Then |2b+c|=

Suppose x^(2)+bx+c {b is an odd integer and c in Z } has two prime natural numbers as its roots . Then |2b+c|=