Determine the Poisson's ratio of the material of a wire whose volume remains constant under an external normal stress.

A uniform wire of length 8m and diameter 0.6mm stretched by 4mm under a certain force. If the Poisson's ratio of the material of the wrie is 0.3, calculate the change in diameter of the wire.

A uniform wire of length 10 m and diameter 0.6 mm is stretched by 6 mm with certain force. If the Poisson's ratio of the material of the wire is 0.3, then the change in diameter of the wire is

A wire of length L and radius r is loaded with a weigth Mg. If y and sigma denote the Youngs modulus and Poisson's ratio of the material of the wire respectively. Then the decreases in the radius of the wire is given by

A wire is stretched by 1% but volume remains constant, then -

When a load of 10 kg is suspended from one end of a wire of length 1m, it increases in length by 0.1 cm. IF the Poisson's ratio for the material of the wire is 1/3 , then calculate the change in volume of the wire, cross-sectional area of the wire =0.1 cm^2 .

The Poisson's ratio of the material of a wire is 0.25. If it is stretched by a force F, the longitudinal strain produced in the wire is 5xx10^(-4) . What is the percentage increase in its volume?

The poisson ratio for the material of a wire is 0.4. When a force is applied on the wire, longitudinal strain is (1/100) . The perecentage change in the radius of the wire is