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A particle is moving in SHM in a straigh...

A particle is moving in SHM in a straight line. When the distance of the particle from equilibrium position has values `x_(1)` and `x_(2)` , the corresponding values of velocities are `u_(1)` and `u_(2)`. Show that time period of vibration is `T=2pi[(x_(2)^(2)-x_(1)^(2))/(u_(1)^(2)-u_(2)^(2))]^(1//2)`

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(a) The motion of the particle in simple harmonic motion is given by x = a sin omega t . If its speed is u , when the displacement is x_(1) and speed is v , when the displacement is x_(2) , show that the amplitude of the motion is A = [(v^(2)x_(1)^(2) - u^(2)x_(2)^(2))/(v^(2) - u^(2))]^(1//2) (b) A particle is moving with simple harmonic motion is a straight line. When the distance of the particle from the equilibrium position has the values x_(1) and x_(2) the corresponding values of velocity are u_(1) and u_(2) , show that the period is T = 2pi[(x_(2)^(2) - x_(1)^(2))/(u_(1)^(2) - u_(2)^(2))]^(1//2)

(a) The motion of the particle in simple harmonic motion is given by x = a sin omega t . If its speed is u , when the displacement is x_(1) and speed is v , when the displacement is x_(2) , show that the amplitude of the motion is A = [(v^(2)x_(1)^(2) - u^(2)x_(2)^(2))/(v^(2) - u^(2))]^(1//2) (b) A particle is moving with simple harmonic motion is a straight line. When the distance of the particle from the equilibrium position has the values x_(1) and x_(2) the corresponding values of velocity are u_(1) and u_(2) , show that the period is T = 2pi[(x_(2)^(2) - x_(1)^(2))/(u_(1)^(2) - u_(2)^(2))]^(1//2)

A particle is moving with shm in a straight line. When the distance of the particle from the equilibrium position has the value x_1 and x_2 the corresponding values of velocities are v_1 and v_2 show that period is T=2pi[(x_2^2-x_1^2)/(v_1^2-v_2^2)]^(1//2)

A particle moves with simple harmonic motion in a straight line. When the distances of the particle from the equilibrium position are x_(1) and x_(2) , the corresponding velocities are u_(1) and u_(2) . Find the period of the moton.

For a linear SHM, when the distance of the oscillator from the equilibrium position has values y_(1)" and "y_(2) the velocities are v_(1)" and "v_(2) . Show that the time period of oscillation is T= 2pi [(y_(2)^(2) -y_(1)^(2))/(v_(1)^(2)-v_(2)^(2))]^(1/2) .

A particle is executing SHM along a straight line. Its velocities at distance X_(1) and X_(2) from mean position are V_(1) and V_(2) , respectively. Its time period is :

A particle is executing SHM along a straight line. Its velocities at distances x_(1) and x_(2) from the mean position are v_(1) and v_(2) , respectively. Its time period is

A particle is executing SHM along a straight line. Its velocities at distances x_(1) and x_(2) from the mean position are v_(1) and v_(2) , respectively. Its time period is

A particle is executing SHM along a straight line. Its velocities at distances x_(1) and x_(2) from the mean position are v_(1) and v_(2) , respectively. Its time period is