Home
Class 12
PHYSICS
A reactor is developing nuclear energy a...

A reactor is developing nuclear energy at a rate of 32,000 kilowatts. How many of `.^235U` undergo fission per second ? How many `.^235U` would be used up in 1000 hour op operation? Assume an average energy of 200MeV released per fission. Take Avogadro's number as `6xx10^(23)`and `1MeV=1.6xx10^(-13)J`.

Promotional Banner

Similar Questions

Explore conceptually related problems

A reactor is developing nuclear energy at a rate of 32,000 kilowatt. How many kg of U^235 undergo fission per second? How many kg of U^235 would be used up in 1000 hour of operation? Assume an average energy of 200 MeV released per fission? Take Avogadro.s number as 6 xx 10^23 and 1 MeV = 1.6 xx 10^(-13) joule

A reaction develop nuclear energy at the rate of 3 xx 10^(4) kW . How many atoms of .^(215)U undergo fission per second? How much .^(235)U is burnt in 1000 hours of operation ? (Assume that 200 Mev is released per fission and Avogadro constant is 6.023 xx 10^(26) per kg mole)

A reactor is developing energy at the rate of 3000 kW. How many atoms of U^(235) undergo fission per second, if 200 MeV energy is released per fission?

A uranium rector develops thermal energy at a rate of 300 MW. Calculate the amount of ^235U being consumed every second .Average energy released per fission is 200 MeV.

Calculate the energy released by the fission 1 g of .^235U in joule, given that the energy released per fission is 200 MeV. (Avogadro.s number = 6.023 xx 10^23 )

A power reactor develops energy at the rate of 30,000 kW. How many gram of ""^(235)U would be consumed daily? Assuming that on an average 200 MeV energy is released per fission.

Calculate the energy released by the fission 1 g of .^(235)U in joule, given that the energy released per fission is 200 MeV . (Avogadro's number =6.023xx10^(23))