Divide the number 24 into two parts such that the ratio of their product to the sum of their squares is 3:10

Explanation

according to question
`(x*(24-x))/(x^2+(24-x)^2)=3/10`

`10x(24-x)=3x^2+3(24-x)^2`

`16x^2-384x+1728=0`

`16(x^2-24x+108)=0`

`x(x-18)-6(x-18)=0`

`(x-6)(x-18)=0`

`x=6,18`

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