A particle executes SHM of period 12s. Two sec after it passes through the centre of oscillation, the velocity is found to be 3.142 cm `s^(-1)` fin dht amplitude and the length of the path.

A particle executes SHM of period 12s. Two sec after it passes through the centre of oscillation, the velocity is found to be 3.142 cm s^(-1) find the amplitude and the length of the path.

A particle executes SHM, its time period is 16 s. If it passes through the centre of oscillation, then its velocity is 2 ms^(-1) at times 2 s. The amplitude will be

A particle executes simple harmonic motion of period 16 s . Two seconds later after it passes through the center of oscillation its velocity is found to be 2 m//s . Find the amplitude.

A particle executes simple harmonic motion of period 16 s . Two seconds later after it passes through the center of oscillation its velocity is found to be 2 m//s . Find the amplitude.

A particle executes SHM in a line 4 cm long. Its velocity when passing through the centre of line is 12 cm/s . The period will be

A particle executes S.H.M. of period 10 sec and amplitude 5cm. Calculate its maximum acceleration and maximum velocity.

A particle executes a linear S.H.M. of amplitude 8 cm and period 2s. The magnitude of its maximum velocity is

A particle executes SHM of period 1.2 s and amplitude 8 cm. Find the time it takes to travel 4 cm from the positive extremity of its oscillation.

A particle executes S.H.M. of period 1.2 s and amplitude 8 cm. What is the time taken to travel 2.344 cm from the positive extremity?

The periodic time of a particle performing a linear S.H.M. is 12 sec. It starts from the mean position. After 2 seconds, its velocity is found to be pi cm//sec . What is the amplitude of S.H.M. ?