Find the equation of tangent to the curve `x=a(theta+sintheta)`,`y=a(1-costheta)` at a point `theta`

Find the equation of the tangent to the curve x=theta+sintheta,y=1+costheta at theta=pi/4dot

Find the equation of the tangent to the curve x=theta+sintheta , y=1+costheta at theta=pi//4 .

Find the equation of the tangent to the curve x=theta+sintheta , y=1+costheta at theta=pi//4 .

Find the equation of the tangent to the curve x=theta+sin theta,y=1cos theta at theta=(pi)/(4)

Find the equations of tangent and normal to the curve x=a( theta- sin theta), y=a(1 -cos theta)" at "theta=pi//2

The equation of the normal to the curve x=a(theta-sintheta),y=a(1-costheta) at (theta=pi//2) is

Find the equation of the tangent line to the curve x = theta + sin theta, y = 1 + cos theta at theta = pi/4

The equation of tangent to the curve x=a(theta+ sin theta), y=a (1+ cos theta)" at "theta=(pi)/(2) is

Find the slope of the tangent to the curve: x = a(theta-sintheta), y = a(1-costheta) at theta = pi/2