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In DeltaABC , the value of (cotA/2cotB/...

In `DeltaABC` , the value of `(cotA/2cotB/2-1)/(cotA/2cotB/2)` is

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If A+B =225^(@) then the value of (cotA)/(1+cotA).(cotB)/(1+cotB) is

cot(A+B)=(cotA.cotB-1)/(cotB+cotA)

Prove that- cot(A+B)=(cotA.cotB-1)/(cotA+cotB)

If in a DeltaABC, the value of cotA, cotB, cotC are in A.P. show a^2,b^2,c^2 are in A.P.

In DeltaABC , (b-c)cotA/2+(c-a)cotB/2+(a-b)cotC/2=?

In DeltaABC , (b-c)cotA/2+(c-a)cotB/2+(a-b)cotC/2=?

cot(A-B)=(cotA.cotB+1)/(cotB-cotA)

cot(A-B)=(cotA.cotB+1)/(cotB-cotA)

In DeltaABC,(cot(A//2)+cot(B//2)+cot(C//2))/(cotA+cotB+cotC)=