A pendulum bob has a speed 3m/s while passing thorugh its lowest position. What is its speed when it makes an angle of `60^0` with the vertical? The length of the pendulum is 0.5m Take `g=10 m/s^2`.

A pendulum bob has a speed 3m/s while passing through its lowest position. What is its speed when it makes an angle of 60^0 with the vertical? The length of the pendulum is 0.5m Take g=10 m/s^2 .

A pendulum bob has a speed 3m/s while passing through its lowest position. What is its speed when it makes an angle of 60^0 with the vertical? The length of the pendulum is 0.5m Take g=10 m/s^2 .

The bob of a pendulum is moving with a speed of 5 m/s while passing through mean position . Calculate its speed at the position when it makes an angle of 30^(@) with the vertical . The length of pendulum is 0.6 m / Use g = 10 m//s^(2)

A pendulum bob has a speed of 3m//s at its lowest is position. The pendulum is 0.5m long. The speed of the bob, when string makes an angle of 60^@ to the vertical is

A pendulum bob has a speed of 3ms^(-1) at its lowest position. The pendulum is 0.5 m long. The speed of the bob, when string makes an angle of 60^(@) to the vertical is ("take, g"=10ms^(-1))

A pendulum bob has a speed of 3ms^(-1) at its lowest position. The pendulum is 0.5 m long. The speed of the bob, when string makes an angle of 60^(@) to the vertical is ("take, g"=10ms^(-1))

A pendulum consists of a 2.0 kg stone swinging on a 4.5 m string of negligible mass. The stone has a speed of 8.0 m/s when it passes its lowest point. (a) What is the speed when the string is at 60^(@) to the vertical ? (b) What is the greatest angle with the vertical that the string will reach during the stone's motion ? (c) If the potential energy of the pendulum-Earth system is taken to be zero at the stone's lowest point, what is the total mechanical energy of the system ?

A simple pendulum of length 1/2m has initial speed 3m/s when pendulum mass is at lowermost point. What will be the speed pf pendulum mass, when the string of pendulum makes an angle of 60^0 with vertical.

The mass of a simple pendulum bob is 100 gm. The length of the pendulum is 1 m. The bob is drawn aside from the equilibrium position so that the string makes an angle of 60^(@) with the vertical and let go. The kinetic energy of the bob while crossing its equilibrium position will be