A body starts from rest with an acceleration `2m//s^(2)` till it attains the maximum velocity then retards to rest with `3m//s^(2)`. If total time taken is 10 second, then maximum speed attained is

A body starts from rest with a uniform acceleration of 2 m s^(-1) . Find the distance covered by the body in 2 s.

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.

A car starts from rest and travels with uniform acceleration a, for some time and then with uniform retardation beta and comes to rest. If the total time of car is 't', the maximum velocity attained by it is given by

A body starting from rest and has uniform acceleration 8 m//s^(2) . The distance travelled by it in 5^(th) second will be

A car acceleration from rest at a constant rate 2m//s^(2) for some time. Then, it retards at a constant rate of 4 m//s^(2) and comes to rest. If it remains motion for 3 second, then the maximum speed attained by the car is:-

A car acceleration from rest at a constant rate 2m//s^(2) for some time. Then, it retards at a constant rate of 4 m//s^(2) and comes to rest. If it remains motion for 3 second, then the maximum speed attained by the car is:-

A car acceleration from rest at a constant rate 2m//s^(2) for some time. Then, it retards at a constant rate of 4 m//s^(2) and comes to rest. If it remains motion for 3 second, then the maximum speed attained by the car is:-

A body starts from rest and acquires a velocity 10 m s^(-1) in 2 s. Find the acceleration.

A body starts from rest at time t = 0 , the acceleration time graph is shown in the figure . The maximum velocity attained by the body will be