In order to raise a mass of 100 kg, a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with acceleration `5g//4` relative to the rope. The tension in the rope is (take `g=10 ms^(-2)`)

In order to raise a mass of 100kg a man of mass 60kg fastena a rope to it and passes the rope over a smooth pulley. He climbs the rope with an accelration 5g/4 relative to rope. The tension in the rope is

In order to raise a mass of 100kg a of mass 60kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with acceleration 5g//4 relative to the rope. The tension in the rope is: Take g=10m//s^(2)

To raise a weight which is half as much again as his weight a man fastens a rope to it and passes over a smooth pulley, he then climbs up the rope with an acceleration (6g)/(7) relative to the rope. Show that the weight rises with acceleration (8)/(7) , and find the tension of the rope.

A boy of mass 40kg climbs up a rope with an acceleration of 1.2ms^(-2) .What is the tension in the rope?

A boy of mass 40 kg climbs up a rope with an acceleration of 2 ms^(-2) . What is the tension in the rope ?

A boy of mass 40 kg climbs up a rope with an acceleration of 2 ms^(-2) . What is the tension in the rope ?

Tow men of masses m_(1)and m_(2) hold on the opposite ends of a rope passing over a frictionless pulley. The men m_(1) climbs up the pore with an acceleration of 1.2m//s^(2) relative to the rope. The mann m_(2) climbs up the rope with an acceleration of 2m//s^(2) relative to the rope. Find the tension in the rope if m_(1)40 kg and m_(2)=60kg. Also find the time after the time after which they will be at same horizontal level if they start from rest and are initially separted by 5 m.