" HRA dilloff: "(9^(1/3)times27^(-1/2))/(36^(1/3)times3^(-2/3))

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(9^((1)/(3))times27^((-1)/(2)))/(3^((1)/(6))times3^((-2)/(3)))

Simplify: (9^(1/3)xx27^(-1/2))/(3^(1/6)xx3^(-2/3))

(1(1)/(13)times2(3)/(5))-:(7(1)/(2)times3(1)/(10))-:(28)/(279)

The reciprocal of [((1)/(3))^(2)-((1)/(3))^(3)]times3^(3) is

(1/3times-1/2)times5/6 = (5/6 times 1/3)times-1/2

Find the value of : (-1)times(-2)times(-3)times(-9)

((1)/(3)+1)+3-:9times4

((1)/(3)times(2)/(9))/((1)/(3)times(1)/(5)+(1)/(3)times(1)/(3)+(1)/(3)times(2)/(9))

(9^(n)times3^(2)times3^(n)-(27)^(n))/((3^(3))^(5)times2^(3))=(1)/(27)," find the value of "n

Evaluate the value 3^((1)/(2))times3^((1)/(4))times3^((1)/(3)) ........ .Infinite terms