If two parallel chords of a circle, having diameter 4 units, lie on the opposite sides of the centreand subtend angles `cos^-1(1/7) and sec^-1(7)` at the centre respectively, then the distance betweenthese chords, is: (a) `4/sqrt7` (b) `8/sqrt7` (c) `8/7` (d) `16/7`

If two parallel chords of a circle,having diameter 4 units,lie on the opposite sides of the centreand subtend angles cos^(-1)((1)/(7)) and sec^(-1)(7) at the centre respectively,then the distance betweenthese chords,is: (a) (4)/(sqrt(7)) (b) (8)/(sqrt(7)) (c) (8)/(7) (d) (16)/(7)

7.The distance of the point P(1,7) from the y -axis is : (a) 1 (b) 7 (c) 6 (d) 8

Two chords AB and CD of lengths 24 cm and 10 cm respectively of a circle are parallel. If the chords lie on the same side of the centre and distance between them is 7 cm, find the length of a diameter of the circle.

If theta is an acute angle such that tan^2theta=8/7 , then the value of ((1+sintheta)(1-sintheta))/((1+costheta)(1-costheta) is (a) 7/8 (b) 8/7 (c) 7/4 (d) (64)/(49)

In a circle of radius 7 cm, a chord makes an angle of 60^@ at the centre of the circle. Find area of the circle (Take sqrt3 = 1.73 )

Solve: (1)/(sqrt(3)-8)-(1)/(sqrt(8)-sqrt(7))

The radius of a circle is 6 cm. The perpendicular distance from the centre of the circle to the chord which is 8 cm in length, is (a) sqrt(5)\ c m (b) 2sqrt(5)\ c m (c) 2\ sqrt(7)\ c m (d) sqrt(7)\ c m