Two fixed charges `4Q` (positive) and `Q` (negative) are located at `A` and `B`the distance `AB` being `3m`

Two fixed charges 4Q (positive) and Q (negative) are located at A and B. the distance AB being 3 m.

Two fixed charges 4 Q (positive ) and q (negative ) are located at A and B , ther distance AB being 3 m . .

Two point charges Q_(1) and Q_(2) are positioned at points I and 2. The field intensity to the right of the charge Q_(2) on the line that passes through the two charges varies according to a law that is represented in the figure. The field intensity is assumed to be positive if its direction coincides with the positive direction on the x-axis. The distance between the charges is l. (a) Find the sign of each charge (b) Find the ratio of the absolute values of the charges |(Q_(1))/(Q_(2))| (c) Find the value of b where the field intensity is maximum [(a) Q_(2) is negative and Q_(1) is positive (b) ((l +a)/(a))^(2) , (c) (l)/(((l+a)/(a))^(2//3)-1)]

Two positive charges q_(1) and q_(2) are located at the points with redius vectors r_(1) and r_(2) . Find a negative charge q_(3) and a radius vector r_(3) of the point at which it has to be placed for the force acting on each of the three charges to be equal to zero.

Two connected charges of +q and -q respectively are at a fixed distance AB apart in a non uniform electric field whose lines of force are shown in the figure The resultant effect on the two charges is

Two fixed point charge 4Q and 2Q are separated by a distance x. where should a third point charge q be placed for ti to be in equilibrium?

Two charges +Q " and " -2Q are located at points A and B on a horizontal line as shown below The electric field is zero at a point which is located at a finite distance

Two fixed charges -2Q and +Q are located at points (-3a,0) and (+3a,0) respectively. Then which of the following statement is correct?