Home
Class 11
PHYSICS
A remote sensing satellite of the earth ...

A remote sensing satellite of the earth revolves in a circular orbit at a height of 250 km above the earth's surface. What is the (i) orbital speed and (ii) period of revolution of the satellite ? Radius of the earth, `R=6.38xx10^(6)` m, and acceleration due to gravity on the surface of the earth, `g=9.8 ms^(-2)`.

Promotional Banner

Similar Questions

Explore conceptually related problems

A remote sensing satellite of the Earth in a circular orbit at a height of 400 km above the surface of Earth. What is the (a) orbital speed, and (b) period of revolution of satellite ? Radius of Earth = 6 xx 10^(6) m and acceleration due to gravity the surface of Earth is 10 m//s^(2) .

A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25xx10^6 m above the surface of earth. Find the orbital speed and the period of revolution of satellite . Given : Earth's radius R_e=6.38xx10^6 m and g=9.8 m//s^2 .

A remote- sensing satellite of earth revolves in a circular orbit at a height of 0.25xx10^6m above the surface of earth.If earth 's radius is 6.38xx10^6ms^(-2) then the orbital speed of the satellite is

An earth satellite revolves in a circular orbit at a height of 300 km above the earth's surface with a period of 90 min. What is its speed ? Calculate the radial acceleration of the satellite ? Radius of the earth is 6.38 xx 10^6 m.

An artificial satellite revolves around the earth in a circular orbit and is at a height of 300 km above the surface of the earth. Find the orbital speed and the time period of the satellite. The radius of the earth=6400 km, g=980 cm*s^(-2) .

A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25xx10^(6)m above the surface of earth. If earth's radius is 6.38xx10^(6)m and g=9.8ms^(-2) , then the orbital speed of the satellite is

A remote-sensing satellite of earth revolves in a circular orbit at a hight of 0.25xx10^(6)m above the surface of earth. If earth's radius is 6.38xx10^(6)m and g=9.8ms^(-2) , then the orbital speed of the satellite is

A remote-sensing satellite of earth revolves in a circular orbit at a hight of 0.25xx10^(6)m above the surface of earth. If earth's radius is 6.38xx10^(6)m and g=9.8ms^(-2) , then the orbital speed of the satellite is