In a triangle ABC, show that `s.sec(A/2)sec(B/2)sec(C/2)=2[(abc)/(sinAsinBsinC)]^(1/3)`

For triangle ABC prove that sec((A+B)/2)="cosec"C/2

In any triangle ABC show that b^2sin2C+c^2sin 2B=abc/R

sec^(2)A(1+sec2A)=2sec2A

(sec2A+1)sec^2A=

In triangle ABC, prove that sin""(A)/(2)sin""(B)/(2)sin""(C)/(2)le(1)/(8) and hence, prove that co sec ""(A)/(2)+co sec""(B)/(2)+co sec""(C)/(2)ge6 .

In triangle ABC, prove that sin""(A)/(2)sin""(B)/(2)sin""(C)/(2)le(1)/(8) and hence, prove that co sec ""(A)/(2)+co sec""(B)/(2)+co sec""(C)/(2)ge6 .

In triangle ABC, prove that sin""(A)/(2)sin""(B)/(2)sin""(C)/(2)le(1)/(8) and hence, prove that co sec ""(A)/(2)+co sec""(B)/(2)+co sec""(C)/(2)ge6 .

If I is the incenter of a triangle ABC, then the ratio IA:IB:IC is equal to cosec (A)/(2):csc(B)/(2):csc(C)/(2)sin(A)/(2):sin(B)/(2):sin(C)/(2)sec(A)/(2):sec(B)/(2):sec(C)/(2) none of these

If Delta ABC , show that sum (b+c) cos A = 2s .

Let AD, BE, CF be the lengths of internal bisectors of angles A, B, C respectively of triangle ABC. Then the harmonic mean of AD"sec"(A)/(2),BE"sec"(B)/(2),CF"sec"(C )/(2) is equal to :