[" (3) "30^(@)],[" A bar of iron is "10cm" at "20^(@)C" .At "19^(@)C" it will be "(alpha_(Fe)=11times10^(-6)/^(@)C)]

A bar of iron is 10 cm at 20^(@)C . At 19^(@)C it will be (alpha_(Fe)=11xx10^(-6)//.^(@)C)

A bar of iron is 10 cm at 20^(@)C . At 19^(@)C it will be (alpha_(Fe)=11xx10^(-6)//.^(@)C)

A bar of iron is 10 cm at 20^(@)C . At 19^(@)C it will be ( alpha of iron =11xx10^-6//^(@)C )

A bar of iron is 10 cm at 20^(@)C . At 19^(@)C it will be ( alpha of iron =11xx10.//^(@)C )

The difference in lengths of an iron and a copper rod, both at 50^(@)C " and " 450^(@)C , is 2 cm. What are the lengths of the two rods at 0^(@)C ? [Given, alpha_(Fe)=12 times 10^(-6@)C^(-1) " and " alpha_(Cu)=17 times 10^(-6@)C^(-1) ]

A brass sheet is 25 cm long and 8 cm breath at 0^(@) C . Its area at 100^(@)C is (alpha = 18 xx 10^(-6 // ^(@))C)

An iron sphere has a radius of 10 cm at a temperature of 0^(@)C . Calculate the change in volume of the sphere if it is heated to 100^(@)C . Given alpha_(Fe) = 1.1 xx 10^(-6).^(@)C^(-1)