[" 23.Calculate the electronegativity of fluorine frunts "],[" following data: "],[E_(H-H)=104.2kcalmol^(-1)E_(F-F)=36.2kalm],[E_(H-F)=134.6kcalmol^(-1)quad X_(H)=2.1]

Calculate the electronegativity of fluorine from the following data E_H-H=104.2Kcal mol^(-1) , E_F-F=36.6 Kcal mol^(-1) , E_H-F=134.6 Kcal mol^)-1)

Calculate the electronegativity of fluorine from the following data: E_(H-H) = 104.4 kcal mol^(-1), E_(F-F) = 36.6 kcal mol^(-1) E_(H-F) = 134.3 kcal mol^(-1), chi_(H) = 2.1

Calculate the electronegativity of fluorine from the following data: E_(H-H) = 104.4 kcal mol^(-1), E_(F-F) = 36.6 kcal mol^(-1) E_(H-F) = 134.3 kcal mol^(-1), chi_(H) = 2.1

Calculate the electronegativity of fluorine from following data : E_(H - H) = 104.2 kcal mol^(-1) E_(F - F) = 36.6 kcal mol^(-1) E_(H -F) = 134.6 kcal mol^(-1) Electronegativity of H is 2.05.

Calculate the electronegativity of carbon from the following data: E_(H-H)= 104.2 kcal mol^(-1), E_(C-C)= 83.1kcalmol^(-1), E_(C-H)= 98.8 kcal mol^(-1) X_H=2.1

Calculate the electronegativity of carbon from the following data: E_(H-H)=104.2 kcal mol^(-1) , E_(C-C) =83.1kcal mol^(-1) E_(C-H)=98.8 kcal mol^(-1) X_H=2.1

Calculate the electronegativity of fluorine form the following data : E_(H-H) = 104.2 kcal "mol"^(-1), E_(C-C) =83.1 kcal "mol"^(-1) . E_(C-H) =9.8.s kcal "mo"l^(-1) Electronegativity of H=2.1 .