`10q+4p-3p+4q=`

Show that : (4p q+3q)^2-(4q p-3q)^2=48 p q^2 (a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0

If the difference of the roots of x^2-p x+q=0 is unity, then a) p^2+4q=1 b) p^2-4q=1 c) p^2+4q^2=(1+2q)^2 d) 4p^2+q^2=(1+2p)^2

Find the products: (7p^4+q)(49 p^8-7p^4q+q^2)

If the difference of the roots of x^(2)-px+q=0 is unity,then p^(2)+4q=1b .p^(2)-4q=1c*p^(2)+4q^(2)=(1+2q)^(2)d4p^(2)+q^(2)=(1+2p)^(2)

Find the value of p and q if p-q=1 and 4p-q=16

Subtract 4p^2q-3pq+5pq^2-8p+7q-10 from 18-3p-11q+5pq-2pq^2+5p^2q

If p/q = 6/5 , then find the value of the ratio (5p-6q)/(3p+4q)

(10p + q) (10q + p)=

If p/q=6/5 then the value of (3p+4q)/(3p-4q) is………….