(1-cos A+cos B-cos(A+B))/(1+cos A-cos B-cos(A+B))=tan A/2cot B/2

(1-cos A+cos B-cos(A+B))/(1+cos A-cos B-cos(A+B))=(tan A)/(2)(cot B)/(2)

Prove that (1-cos A+cos B-cos(A+B))/(1+cos A-cos B-cos(A+B))=tan((A)/(2))cot((B)/(2))

If none of A,B, A+B is an integral multiple of pi , then prove that (1- cos A+ cos B- cos (A+B))/(1+ cos A- cos B - cos (A+B))=tan.(A)/(2) cot. (B)/(2)

In Delta ABC, show that (1-cos A+cos B+cos C)/(1-cos C+cos A+cos B)=tan((A)/(2))cot((C)/(2))

1-cos A + cos B-cos (A + B) * AB tan-cot-1 + cos A-cos B-cos (A + B) cod-cod CO-coc0-ces-A cos

If A+ B + C = pi, then cos^(2) A + cos ^(2) B + cos ^(2) C is equal to : A) 1 - cos A cos B cos C B) 1 - 2 cos A cos B cos C C) 2 cos A cos B cos C D) 1 + cos A cos B cos C

cos^(2) (A-B)+cos^(2)B-2cos(A-B) cos A cos B =

(cos A+cos B)/(cos B-cos A)=cot((A+B)/(2))cot((A-B)/(2))

If A+B+C=0, then the value of sin^(2)A+cos C(cos A cos B-cos C)+cos B(cos A cos C-cos B) is equal to: -1 (b) 0(c)1 (d) none of these

Prove that: (cos A+cos B)/(cos B-cos A)=cot((A+B)/2)cot((A-B)/2)