A particle of mass `m` initially at rest starts moving from point `A` on the surface of a fixed smooth hemisphere of radius `r` as shown. The particle looses its contact with hemisphere at point `B.C` is centre of the hemisphere. The equation relating `theta` and `theta'` is
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A particle of mass m is released from the top of a smooth hemisphere of radius R with the horizontal speed mu . Calculate the angle with verticle where it loses contact with the hemisphere.

A small block of mass m has speed sqrt(gR) /2 at the top most point of a fixed hemisphere of radius R as shown in figure. The angle theta , when block loses the contact with the hemisphere is

A particle of mass m is placed in equlibrium at the top of a fixed rough hemisphere of radius R. Now the particle leaves the contact with the surface of the hemisphere at angular position theta with the vertical wheere cos theta""(3)/(5). if the work done against frictiion is (2mgR)/(10x), find x.

A particle of mass m is placed in equilibrium at the top of a fixed rough hemisphere of radius R. Now the particle leaves the contact with the surface of the hemisphere at angular position theta with the vertical where cos theta"="(3)/(5). if the work done against friction is (2mgR)/(10x), find x.

A block of mass as shown is released from rest from top of a fixed smooth hemisphere. Find angle made by this particle with vertical at the instant when it looses contact with hemisphere.

A particle of mass m is going along surface of smooth hemisphere of radius R in verticle plane. At the moment shown its speed is v. Choose correct option(s).

A particle is released from the top of the smooth hemisphere R as shown. the normal contact between the particle and the hemisphere in position theta is

A small block of mass m is released from rest from position A inside a smooth hemispherical bowl of radius R as shown in figure Choose the wrong option.