If `y=2/(sqrt(a^2-b^2)) {tan^-1( (a-b)/(a+b)) tan x/2 } ` then show that `(d^2y)/(dx^2) =(b sin x )/((a+b cos x )^2)`.

If y=2/(sqrt(a^2-b^2)){tan^(-1)sqrt((a-b)/(a+b))tan(x/2)} , then show that (d^2y)/(dx^2)=(bsinx)/((a+bcosx)^2)

If y=2/(sqrt(a^2-b^2))tan^(-1){sqrt((a-b)/(a+b))tan(x/2)} , then show that (d^2y)/(dx^2)=(bsinx)/((a+bcosx)^2)

"If "y=(2)/(sqrt(a^(2)-b^(2))){tan^(-1)(sqrt((a-b)/(a+b))tan""(x)/(2))}," then show that "(d^(2)y)/(dx^(2))=(b sin x)/((a+b cos x)^(2)).

If y = 2/(sqrt(a^2 - b^2)) "tan"^(-1) (sqrt((a + b)/(a - b)) " tan " x/2) , prove that (dy)/(dx) = 1/(a - b cos x)

If y=2/sqrt(a^2-b^2)tan^-1[sqrt((a-b)/(a+b))tan(x/2)] then (d_2y)/(dx^2)|(x=pi/2)|

If y=2/sqrt(a^2-b^2)tan^-1[sqrt((a-b)/(a+b))tan(x/2)] then (d_2y)/(dx^2)|(=),(x=pi/2):|

If y=2/(sqrt (a^2-b^2)) tan ^-1 [(sqrt( a-b)/(a+b)) tan x/2] , show thatdy/dx= 1/(a+b cos x) and (d^2y)/(dx^2)= (bsinx)/((a+b scos x)^2)

If y=(1)/(sqrt(a^(2)-b^(2)))cos^(-1)((a cos x+b)/(a+b cos x)), then (d^(2)y)/(dx^(2))=(i)(b sin x)/((a+b cos x)^(2))( ii) -(b sin x)/((a+b cos x)^(2))( iii) (b cos x)/((a+b cos x)^(2))( iii) -(b cos x)/((a+b cos x)^(2))

2Tan^(-1)((sqrt(a-b))/(a+b)"tan"x/2)=