Let `bar a,bar b,bar c` be three vectors satistying `bar axx bar b =2bar a xx bar c,|bar a|=|bar c|=1bar b=4 and |bar b xx bar c|=sqrt15`. If `bar b-2bar c=lambda bar a` then `lambda` is

bar a, bar b, bar c are three vectros, then prove that: (bar a xx bar b) xx bar c = (bar a. bar c) bar b-(bar b. bar c) bar a.

if bar a+2 bar b+3bar c=bar 0 then bar axxbar b+bar b xx bar c+bar cxx bara = lambda (bar b xx bar c) ,where lambda=

(d) answer ANY one question :1. bar a, bar b and bar c be three vectors such that bar a +bar b+ bar c =0 and |bar a|=1, |bar b|=4,|bar c |=2 . Evlautae bar a.bar b + bar b.bar c+bar c.bar a .

If bar(a),bar(b),bar(c) are three non zero vectors,then bar(a).bar(b)=bar(a).bar(c)rArr

For three vectors bar(a),bar(b) and bar( c ),bar(a)xx(bar(b)xx bar( c ))=(bar(a)xx bar(b))xx bar( c ) then

if bar(a),bar(b),bar(c) are any three vectors then prove that [bar(a),bar(b)+bar(c),bar(a)+bar(b)+bar(c)]=0

[bar(a)xx bar(b)" "bar(a)xx bar( c )" "bar(d)] = …………….

bar(a),bar(b) and bar( c ) are non zero vectors. |(bar(a)xx bar(b))*bar( c )|=|bar(a)||bar(b)||bar( c )| then ……………

If bar r=l(bar b xx bar c)+m(bar c xx bar a)+n(bar a xx bar b) and [bar a bar b bar c]=2 , then l+m+n is equal to

bar(a) , bar(b) and bar(c) are three vectors such that bar(a) + bar(b) + bar(c) = bar(0) and |bar(a)| =2, |bar(b)| =3, |bar(c)| =5 ,then bar(a) . bar(b) + bar(b) . bar(c) + bar(c) . bar(a) equals