`bar a and bar c` are unit vectors and `|bar b| = 4` with `bar a xx bar b=2bara xx bar c`. The angle between `bar a and bar c` is `cos^-1(1/4)`.Then `bar b-2bar c=lambda bar a` If `lambda` is

bar(a),bar(b) and bar( c ) are unit vectors. bar(a).bar(b)=0=bar(a).bar( c ) and the angle between bar(b) and bar( c ) is (pi)/(3) . Then |bar(a)xx bar(b)-bar(a)xx bar( c )|= …………..

bar a, bar b, bar c are three vectros, then prove that: (bar a xx bar b) xx bar c = (bar a. bar c) bar b-(bar b. bar c) bar a.

If bar(a) and bar(c) are unit parallel vectors |bar(b)|=6 then bar(b)-3bar(c)=lambdabar(a) if lambda

Let bar(a), bar(b), bar(c ) be unit vectors, suppose that bar(a). bar(b) = bar(a). bar(c )= 0 and the angle between bar(b) and bar(c ) is pi//6 then show that bar(a)= +-2 (bar(b) xx bar( c))

If bar(a) is a perpendicular to bar(b) and bar(c), |bar(a)|=2, |bar(b)|=3, |bar(c)|=4 and the angle between bar(b) and bar(c) is (2pi)/(3) then |[bar(a) bar(b) bar(c)]| =

bar(a),bar(b) and bar( c ) are three unit vectors. bar(a)_|_bar(b) and bar(a)||bar( c ) then bar(a)xx(bar(b)xx bar( c )) = …………….

if bar a+2 bar b+3bar c=bar 0 then bar axxbar b+bar b xx bar c+bar cxx bara = lambda (bar b xx bar c) ,where lambda=

bar(a)=2hati+hatj-2hatk and bar(b)=hati+hatj . The vector bar( c ) is such that bar(a)*bar( c )=|bar( c )|,|bar( c )-bar(a)|=2sqrt(2) and the angle between bar(a)xx bar(b) and bar( c ) is 30^(@) then |(bar(a)xx bar(b))xx bar( c )| = …………

Let a,b, c be three vectors such that |bar(a)|=1,|bar(b)|=2 and if bar(a)times(bar(a)timesbar(c))+bar(b)=bar(0), then angle between bar(a) and bar(c) can be.